Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.2 - More Work with Exponents and Scientific Notation - Exercise Set - Page 269: 96

Answer

$$\frac {15y^3}{x^{8}}$$

Work Step by Step

We first find the given formula, which is given by the area of the parallelogram. $$ A = \frac{3x^{-1}}{y^{-3}} \times 5x^{-7} $$ We use the rules found in this chapter: $$ a^b \times a ^c = a ^ {b+c}$$ $$ \frac {a^b}{a^c} = a ^ {b-c}$$ $$ a ^ {b^c} = a^{bc}$$ This gives: $$ \frac {15y^3}{x^{7+1}}=\frac {15y^3}{x^{8}}$$
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