Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.2 - More Work with Exponents and Scientific Notation - Exercise Set: 93

Answer

$-3z-14$

Work Step by Step

We are given the expression $3(z-4)-2(3z+1)$. We can simplify by using the distributive property to multiply the terms in parentheses. $(3\times z)+(3\times-4)+(-2\times3z)+(-2\times1)=3z-12-6z-2$ Next, we can group like terms. $(3z-6z)+(-12-2)=-3z-(12+2)=-3z-14$
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