Intermediate Algebra (6th Edition)

$-3z-14$
We are given the expression $3(z-4)-2(3z+1)$. We can simplify by using the distributive property to multiply the terms in parentheses. $(3\times z)+(3\times-4)+(-2\times3z)+(-2\times1)=3z-12-6z-2$ Next, we can group like terms. $(3z-6z)+(-12-2)=-3z-(12+2)=-3z-14$