Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.2 - More Work with Exponents and Scientific Notation - Exercise Set - Page 268: 84

Answer

$7.7\times10^{7}$

Work Step by Step

Using laws of exponents, the given expression simplifies to \begin{align*} & \dfrac{0.0007\times11,000}{0.001\times0.0001} \\\\&= \dfrac{7.0\times10^{-4}\times1.1\times10^{4}}{1.0\times10^{-3}\times1.0\times10^{-4}} \\\\&= (7.0\times1.1\div1.0\div1.0)(10^{-4}\times10^{4}\div10^{-3}\div10^{-4}) \\\\&= 7.7\times10^{-4+4-(-3)-(-4)} \\\\&= 7.7\times10^{7} .\end{align*}
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