Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.2 - More Work with Exponents and Scientific Notation - Exercise Set - Page 268: 80

Answer

$7.5\times10^{-3}$

Work Step by Step

Using laws of exponents, the given expression simplifies to \begin{align*} & \dfrac{0.00016\times300}{0.064\times100} \\\\&= \dfrac{1.6\times10^{-4}\times3\times10^{2}}{6.4\times10^{-2}\times1.0\times10^2} \\\\&= (1.6\times3.0\div6.4\div1.0)(10^{-4}\times10^{2}\div10^{-2}\div10^{2}) \\\\&= 0.75\times10^{-4+2-(-2)-2} \\\\&= 0.75\times10^{-2} \\\\&= 7.5\times10^{-3} .\end{align*}
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