Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.2 - More Work with Exponents and Scientific Notation - Exercise Set - Page 268: 67

Answer

$\dfrac{5}{x^{a}y^{a-2}}$

Work Step by Step

\text{ Using laws of exponents, the given expression simplifies to }\\ \begin{align*} & \dfrac{25x^{2a+1}y^{a-1}}{5x^{3a+1}y^{2a-3}} \\\\&= (25\div5)x^{2a+1-(3a+1)}y^{a-1-(2a-3)} \\\\&= 5x^{2a+1-3a-1}y^{a-1-2a+3} \\\\&= 5x^{-a}y^{-a+2} \\\\&= \dfrac{5}{x^{a}y^{a-2}} .\end{align*}
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