Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.2 - More Work with Exponents and Scientific Notation - Exercise Set: 5

Answer

$9x^{4}y^{6}$

Work Step by Step

We are given the expression $(3x^{2}y^{3})^{2}=(3)^{2}\times(x^{2})^{2}\times(y^{3})^{2}$. To simplify further, we can use the power rule, which holds that $(a^{m})^{n}=a^{m\times n}$ (where a is a real number, and m and n are integers). $(3)^{2}\times(x^{2})^{2}\times(y^{3})^{2}=9\times x^{2\times2}\times y^{3\times2}=9x^{4}y^{6}$
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