Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.2 - More Work with Exponents and Scientific Notation - Exercise Set - Page 268: 22

Answer

$\dfrac{64}{25}$

Work Step by Step

Using laws of exponents, the given expression simpifies to \begin{align*} & \left( \dfrac{5}{8} \right)^{-2} \\\\&= \dfrac{5^{-2}}{8^{-2}} \\\\&= \dfrac{8^{2}}{5^{2}} \\\\&= \dfrac{64}{25} .\end{align*}
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