Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.2 - More Work with Exponents and Scientific Notation - Exercise Set: 10

Answer

$\frac{x^{12}}{36y^{14}}$

Work Step by Step

We are given the expression $(6x^{-6}y^{7}z^{0})^{-2}$. To simplify, we can use the power rule, which holds that $(a^{m})^{n}=a^{m\times n}$ (where a is a real number, and m and n are integers). $(6x^{-6}y^{7}z^{0})^{-2}=(6^{-2})\times(x^{-6\times-2})\times(y^{7\times-2})\times(z^{0\times-2})=$ $(6^{-2})\times(x^{12})\times(y^{-14})\times(z^{0})=\frac{x^{12}\times1}{6^{2}y^{14}}=\frac{x^{12}}{36y^{14}}$
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