## Intermediate Algebra (6th Edition)

$y^{7}$
We are given the expression $(y^{7})^{5}$. Recall that an exponential expression consists of a factor, known as the base, and an exponent. The number of times that the base is multiplied is indicated by the value of the exponent. Therefore, $y^{7}$ is the base of the exponent 5. Multiplied out, $(y^{7})^{5}=(y^{7}\times y^{7}\times y^{7}\times y^{7}\times y^{7})$