Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.1 - Exponents and Scientific Notation - Exercise Set - Page 262: 94

Answer

$x^{2y}$

Work Step by Step

We are given the expression $x^{9y}\times x^{-7y}$. We can use the product rule to simplify, which holds that $a^{m}\times a^{n}=a^{m+n}$ (where a is a real number, and m and n are positive integers). $x^{9y}\times x^{-7y}=x^{9y+(-7y})=x^{2y}$
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