Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.1 - Exponents and Scientific Notation - Exercise Set: 80

Answer

$\frac{y}{25}$

Work Step by Step

We are given the expression $5^{-2}\times y$. To simplify this into a positive exponent, we know that $a^{-n}=\frac{1}{a^{n}}$ (where a is a nonzero real number and n is a positive integer). $5^{-2}\times y=\frac{y}{5^{2}}=\frac{y}{25}$
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