Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.1 - Exponents and Scientific Notation - Exercise Set: 78

Answer

$36a^{5}b^{10}$

Work Step by Step

We are given the expression $(-6a^{4}b)(2b^{3})(-3ab^{6})$. We can simplify by first grouping like terms. $(-6\times2\times-3)\times(a^{4}\times a)\times(b\times b^{3}\times b^{6})$ Next we can use the product rule, which holds that $a^{m}\times a^{n}=a^{m+n}$ (where a is a real number, and m and n are positive integers). $36\times (a^{4+1})\times (b^{1+3+6})=36a^{5}b^{10}$
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