Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.1 - Exponents and Scientific Notation - Exercise Set: 63

Answer

$\frac{1}{z^{3}}$

Work Step by Step

We are given the expression $\frac{z^{12}}{z^{15}}$. We can use the quotient rule to simplify this expression. $\frac{z^{12}}{z^{15}}=z^{12-15}=z^{-3}$ We know that $a^{-n}=\frac{1}{a^{n}}$ (where a is a nonzero real number and n is a positive integer). Therefore, $z^{-3}=\frac{1}{z^{3}}$
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