Answer
6
Work Step by Step
We are given the expression $(5x)^{0}+5x^{0}$.
$(5x)^{0}+5x^{0}=1+5(x)^{0}=1+5\times1=6$
In general, $a^{0}$ will be 1 when a does not equal 0. In the second term, 5 and x are not in parentheses, so only x (the base of the exponent) is evaluated by the exponent.