Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.1 - Exponents and Scientific Notation - Exercise Set: 56

Answer

$27y^{5}$

Work Step by Step

We are given the expression $-3y\times-9y^{4}$. We can simplify by grouping like terms. $(-3\times-9)\times(y\times y^{4})$ Next, we can use the product rule, which holds that $a^{m}\times{a^{n}}=a^{m+n}$ (where a is a real number, and m and n are positive integers). $27\times(y^{1+4})=27y^{5}$
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