Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.1 - Exponents and Scientific Notation - Exercise Set: 54

Answer

$\frac{6z^{11}}{11}$

Work Step by Step

We are given the expression $\frac{(30z^{2})(z^{5})}{55z^{-4}}$. We can first use the product rule to simplify. $\frac{(30z^{2})(z^{5})}{55z^{-4}}=\frac{30z^{2+5}}{55z^{-4}}=\frac{30z^{7}}{55z^{-4}}$ Next, we can use the quotient to further simplify. $\frac{30z^{7}}{55z^{-4}}=\frac{30}{55}\times(z^{7-(-4)})=\frac{6z^{11}}{11}$
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