## Intermediate Algebra (6th Edition)

$\frac{6x^{16}}{5}$
We are given the expression $\frac{(24x^{8})(x)}{20x^{-7}}$. We can first use the product rule to simplify. $\frac{(24x^{8})(x)}{20x^{-7}}=\frac{24x^{8+1}}{20x^{-7}}=\frac{24x^{9}}{20x^{-7}}$ Next, we can use the quotient to further simplify. $\frac{24x^{9}}{20x^{-7}}=\frac{24}{20}\times(x^{9-(-7)})=\frac{6x^{16}}{5}$