Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.1 - Exponents and Scientific Notation - Exercise Set: 53

Answer

$\frac{6x^{16}}{5}$

Work Step by Step

We are given the expression $\frac{(24x^{8})(x)}{20x^{-7}}$. We can first use the product rule to simplify. $\frac{(24x^{8})(x)}{20x^{-7}}=\frac{24x^{8+1}}{20x^{-7}}=\frac{24x^{9}}{20x^{-7}}$ Next, we can use the quotient to further simplify. $\frac{24x^{9}}{20x^{-7}}=\frac{24}{20}\times(x^{9-(-7)})=\frac{6x^{16}}{5}$
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