Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.1 - Exponents and Scientific Notation - Exercise Set: 52

Answer

$\frac{6a^{4}}{b^{12}}$

Work Step by Step

We are given the expression $\frac{18ab^{-6}}{3a^{-3}b^{6}}$. We can use the quotient rule to simplify. $\frac{18ab^{-6}}{3a^{-3}b^{6}}=\frac{18}{3}\times(a^{1-(-3)})\times(b^{-6-6})=6a^{4}b^{-12}$ We know that $a^{-n}=\frac{1}{a^{n}}$, so this expression further simplifies to $\frac{6a^{4}}{b^{12}}$.
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