Answer
$\frac{1}{y^{14}}$
Work Step by Step
We are given the expression $\frac{y^{-7}y}{y^{-8}}$.
To simplify, we can first use the product rule, which holds that $a^{m}\times a^{n}=a^{m+n}$.
$\frac{y^{-7+1}}{y^{-8}}=\frac{y^{-6}}{y^{8}}$
Next, we can use the quotient rule, which holds that $\frac{a^{m}}{a^{n}}=a^{m-n}$.
$y^{-6-8}=y^{-14}$
Finally, we know that $a^{-n}=\frac{1}{a^{n}}$, so $y^{-14}=\frac{1}{y^{14}}$