Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.1 - Exponents and Scientific Notation - Exercise Set: 44

Answer

$\frac{q^{3}}{p^{13}}$

Work Step by Step

We are given the expression $\frac{p^{-13}}{q^{-3}}$. In general, we know that $a^{-n}=\frac{1}{a^{n}}$ (where a is a nonzero real number and n is an integer). Therefore, $\frac{p^{-13}}{q^{-3}}=\frac{1}{p^{13}}\times q^{3}=\frac{q^{3}}{p^{13}}$.
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