Intermediate Algebra (6th Edition)

$\frac{q^{3}}{p^{13}}$
We are given the expression $\frac{p^{-13}}{q^{-3}}$. In general, we know that $a^{-n}=\frac{1}{a^{n}}$ (where a is a nonzero real number and n is an integer). Therefore, $\frac{p^{-13}}{q^{-3}}=\frac{1}{p^{13}}\times q^{3}=\frac{q^{3}}{p^{13}}$.