Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.1 - Exponents and Scientific Notation - Exercise Set: 36

Answer

$\frac{1}{8}$

Work Step by Step

We are given the expression $2^{-3}$. In general, $a^{-n}=\frac{1}{a^{n}}$, where a is a nonzero real number and n is a positive integer. Therefore, $2^{-3}=\frac{1}{2^{3}}=\frac{1}{2\times2\times2}=\frac{1}{8}$
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