Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.1 - Exponents and Scientific Notation - Exercise Set: 31

Answer

$\frac{4x^{3}y^{2}}{3}$

Work Step by Step

We are given the expression $\frac{12x^{4}y^{7}}{9xy^{5}}$. We can simplify this expression by using the quotient rule, which holds that $\frac{a^{m}}{a^{n}}=a^{m-n}$ (where a is a nonzero real number, and m and n are integers). $\frac{12x^{4}y^{7}}{9xy^{5}}=(\frac{12}{9})\times(x^{4-1})\times(y^{7-5})=\frac{4x^{3}y^{2}}{3}$
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