Answer
$\frac{4x^{3}y^{2}}{3}$
Work Step by Step
We are given the expression $\frac{12x^{4}y^{7}}{9xy^{5}}$.
We can simplify this expression by using the quotient rule, which holds that $\frac{a^{m}}{a^{n}}=a^{m-n}$ (where a is a nonzero real number, and m and n are integers).
$\frac{12x^{4}y^{7}}{9xy^{5}}=(\frac{12}{9})\times(x^{4-1})\times(y^{7-5})=\frac{4x^{3}y^{2}}{3}$