Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.1 - Exponents and Scientific Notation - Exercise Set: 28

Answer

$-2x^{4}$

Work Step by Step

We are given the expression $-\frac{16x^{5}}{8x}$. We can simplify this expression by using the quotient rule, which holds that $\frac{a^{m}}{a^{n}}=a^{m-n}$ (where a is a nonzero real number, and m and n are integers). $-\frac{16x^{5}}{8x}=(-\frac{16}{8})\times(x^{5-1})=-2x^{4}$
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