Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.1 - Exponents and Scientific Notation - Exercise Set: 27

Answer

$-13z^{4}$

Work Step by Step

We are given the expression $-\frac{26z^{11}}{2z^{7}}$. We can simplify this expression by using the quotient rule, which holds that $\frac{a^{m}}{a^{n}}=a^{m-n}$ (where a is a nonzero real number, and m and n are integers). $-\frac{26z^{11}}{2z^{7}}=(-\frac{26}{2})\times(z^{11-7})=-13z^{4}$
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