Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.1 - Exponents and Scientific Notation - Exercise Set - Page 262: 20

Answer

1

Work Step by Step

We are asked to evaluate the expression $(3x-1)^{0}$. In general, $a^{0}=1$ when a does not equal 0. Therefore, $(3x-1)^{0}=1$, where $a=(3x-1)$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.