Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.1 - Exponents and Scientific Notation - Exercise Set: 16

Answer

$18a^{3}b^{6}$

Work Step by Step

We are given the expression $(-6a^{2}b^{3})(-3ab^{3})$. We can group like terms to simplify. $(-6\times-3)\times(a^{2}\times a)\times (b^{3}\times b^{3})$ To simplify the second and third terms, we can use the product rule, which holds that $a^{m}\times a^{n}=a^{m+n}$ (where a is a real number, and m and n are positive integers). $18\times a^{2+1} \times b^{3+3}=18a^{3}b^{6}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.