Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.1 - Exponents and Scientific Notation - Exercise Set: 15

Answer

$-16x^{6}y^{3}p^{2}$

Work Step by Step

We are given the expression $(-4x^{3}p^{2})(4y^{3}x^{3})$. We can group like terms to simplify. $(-4\times4)\times(x^{3}\times x^{3})\times y^{3} \times p^{2}$ To simplify the second term, we can use the product rule, which holds that $a^{m}\times a^{n}=a^{m+n}$ (where a is a real number, and m and n are positive integers). $-16\times x^{3+3}\times y^{3} \times p^{2}=-16x^{6}y^{3}p^{2}$
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