Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.1 - Exponents and Scientific Notation - Exercise Set: 14

Answer

$-49xy^{2}$

Work Step by Step

We are given the expression $(-7xy)(7y)$. $(-7xy)\times(7y)=(-7\times7)\times(x)\times(y\times y)$ We can use the product rule to simplify the third term, which holds that $a^{m}\times a^{n}=a^{m+n}$. Therefore, $(-7\times7)\times(x)\times(y\times y)=-49\times x\times y^{1+1}=-49xy^{2}$
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