Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.1 - Exponents and Scientific Notation - Exercise Set - Page 262: 101

Answer

$1.6\times10^{-2}$

Work Step by Step

We are given the number $.016$. Step 1: To write this number in scientific notation, we move the decimal point to the right until the original number is 1.6. Step 2: Since the original number was less than 1, we moved the decimal by 2 negative places. In other words, we will raise 10 to a power of -2. Now, we write the product of the two numbers found in Step 1 and Step 2. $1.6\times10^{-2}$
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