Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 4 - Sections 4.1-4.3 - Integrated Review - Systems of Linear Equations - Page 234: 18

Answer

Solution set is $\{ (x,y,z) | x-y+3z =2\}$.

Work Step by Step

$x-y+3z = 2$ Equation $(1)$ $-2x+2y-6z = -4$ Equation $(2)$ $3x-3y+9z = 6$ Equation $(3)$ Multiply Equation $(1)$ by $2$ $2x-2y+6z = 4$ Equation $(4)$ Adding Equation $(2)$ and Equation $(4)$ $-2x+2x +2y-2y -6z+6z = -4+4$ $0=0$ This statement is true for all values of $x,y$ and $z$. There are infinitely many solutions. The solution set is $\{ (x,y,z) | x-y+3z =2\}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.