Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 4 - Section 4.3 - Systems of Linear Equations and Problem Solving - Exercise Set - Page 231: 13

Answer

The first number is $-10$ and the second number is $-8$.

Work Step by Step

$x = y-2$ Equation $(1)$ $2x = 3y+4$ Equation $(2)$ Substitute $x$ into Equation $(2)$. $2(y-2) = 3y+4$ $2y-4 = 3y+4$ $-y=8$ $y=-8$ Substitute $y$ into Equation $(1)$. $x = -8-2$ $x = -10$ The first number is $-10$ and the second number is $-8$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.