Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 4 - Section 4.3 - Systems of Linear Equations and Problem Solving - Exercise Set - Page 230: 2

Answer

Thus, the first number is 5, and the second number is 7.

Work Step by Step

Using the hints provided, we create the two equations: $3x-y= 8$ $x+y=12$ We substitute to find: $3(12-y)-y=8$ This gives: $36-4y=8$ $y = 7$ Since the sum of the numbers is 12: $x = 12-7 = 5 $ Thus, the first number is 5, and the second number is 7.
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