Answer
$(-2,5,1)$
Work Step by Step
$x+y = 3$ Equation $(1)$
$2y=10$ Equation $(2)$
$3x+2y-3z = 1$ Equation $(3)$
From Equation $(2)$, we get
$2y=10$
$y = 5$
Substituting $y$ value in Equation $(1)$
$x+y = 3$
$x+5 = 3$
$x = 3-5$
$x = -2$
Substituting $x$ and $y$ values in Equation $(3)$
$3x+2y-3z = 1$
$3(-2)+2(5)-3z = 1$
$-6+10-3z = 1$
$4-3z = 1$
$-3z = 1-4$
$-3z = -3$
$z = 1$
$x = -2$
$y=5$
$z= 1$
Solution is $(-2,5,1)$