Answer
$$(1/3,0,-2)$$
Work Step by Step
We add the first two equations to find: $$ 6x-4y=2$$ We add this to the third equation to obtain: $$ 3z=-6$$ $$z=-2$$ Next, we find x. We substitute z into the first two equations, and then we subtract the second from the first to find: $$-2y-4=-4$$ This gives: $$y=0$$ Lastly, we find x, substituting y and z into the original first equation: $$3x-3(0)+(-2)=-1$$ $$x=1/3$$ Thus, the solution is: $$(1/3,0,-2)$$