Answer
Ordered Pair Solution $(\frac{1}{4},8)$
Work Step by Step
We have $$1)\frac{1}{x}+y=12$$ $$2)\frac{3}{x}-y=4$$
(1)+(2) $$\frac{4}{x} = 16$$ $$x=\frac{1}{4}$$
Solving for $y$ $$y = 12-1\div\frac{1}{4}=8$$
Ordered Pair Solution $(\frac{1}{4},8)$