Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 4 - Section 4.1 - Solving Systems of Linear Equations in Two Variables - Exercise Set - Page 212: 44

Answer

This system has no solution.

Work Step by Step

$3x+6y=15$ $2x+4y=3$ To equate the coefficients, multiply both sides of the first equation by 2. $2(3x+6y)=2(15)\longrightarrow$ Simplify. Apply the distributive property. $6x+12y=30$ To equate the coefficients, multiply both sides of the second equation by 3. $3(2x+4y)=3(3)\longrightarrow$ Simplify. Apply the distributive property. $6x+12y=9$ Subtract the two new equations. $\ \ \ \ 6x+12y=30$ $\underline{-(6x+12y=9)}$ $\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0=21$ Since solving the system of equations results in a false statement, the system has no solution.
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