Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 4 - Section 4.1 - Solving Systems of Linear Equations in Two Variables - Exercise Set - Page 212: 27

Answer

Ordered pair solution $(8,2)$

Work Step by Step

We have $$(1) \frac{3}{4}x+\frac{5}{2}y=11$$ $$(2)\frac{1}{16}x-\frac{3}{4}y=-1$$ Multiply (2) by $-12$ and add (1) $$ \frac{3}{4}x -\frac{3}{4}x+\frac{5}{2}y + 9y=11 + 12$$ $$\frac{23}{2}y = 23$$ $$y=2$$ Solving for $x$ $$x = (11-\frac{5}{2}*2)*\frac{4}{3} = 8$$ Ordered pair solution $(8,2)$
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