Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 4 - Review - Page 250: 19

Answer

20 liters of the 10% solution and 30 liters of the 60% solution

Work Step by Step

10% and 60% solution 50 liters needed Let $x$ and $y$ be the amounts of the 10% and 60% solutions used, respectively. $x+y=50$ $.1x+.6y=50*.4$ $.1x+.6y=20$ $x+y=50$ $x+y-y=50-y$ $x=50-y$ $.1x+.6y=20$ $.1(50-y)+.6y=20$ $.1*50-y*.1+.6y=20$ $5-.1y+.6y=20$ $5+.5y=20$ $5+.5y-5=20-5$ $.5y=15$ $.5y*2=15*2$ $y=30$ $x+y=50$ $x+30=50$ $x+30-30=50-30$ $x=20$
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