Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 4 - Review - Page 249: 7

Answer

$(2,0,2)$

Work Step by Step

Given Equations, $x+z=4$ Equation $(1)$ $2x-y=4$ Equation $(2)$ $x+y-z=0$ Equation $(3)$ Adding Equation $(1)$ and Equation $(2)$ $x+z+2x-y=4+4$ $3x-y+z=8$ Equation $(4)$ Adding Equation $(3)$ and Equation $(4)$ $x+y-z+3x-y+z=0+8$ $4x=8$ $x=2$ Substituting $x$ value in Equation $(1)$ $x+z=4$ $2+z=4$ $z=2$ Substituting $x$ value in Equation $(2)$ $2x-y=4$ $2(2)-y=4$ $4-y=4$ $-y=0$ $y=0$ Solution: $(2,0,2)$
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