Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 4 - Review - Page 249: 5

Answer

$(3, \frac{8}{3})$ Please see the graph.

Work Step by Step

$1/2*x-3/4*y=-1/2$ $1/8*x+3/4*y=19/8$ $1/2*x-3/4*y+1/8*x+3/4*y=-1/2+19/8$ $5/8*x = 15/8$ $5/8*x*8/5 = 15/8*8/5$ $x=3$ $1/2*x-3/4*y=-1/2$ $1/2*3-3/4*y=-1/2$ $3/2-3/4*y=-1/2$ $3/2-3/4*y-3/2=-1/2-3/2$ $-3/4*y = -2$ $-3/4*y*-4/3 = -2*-4/3$ $y = 8/3$ $1/2*x-3/4*y=-1/2$ $1/2*x-3/4*y+1/2+3/4*y=-1/2+1/2+3/4*y$ $1/2*x+1/2=3/4*y$ $4*(1/2*x+1/2)=3/4*y*4$ $2x+2=3y$ $(2x+2)/3=3y/3$ $2/3*x+2/3=y$ $1/8*x+3/4*y=19/8$ $1/8*x+3/4*(2/3*x+2/3)=19/8$ $1/8*x+1/2*x+1/2=19/8$ $5/8*x+1/2=19/8$ $8*(5/8*x+1/2=19/8)$ $5x+4=19$ $5x+4-4=19-4$ $5x=15$ $5x/5=15/5$ $x=3$ $2/3*x+2/3=y$ $2/3*3+2/3=y$ $2+2/3=y$ $8/3=y$
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