Answer
Refer to the attached image for the plot of the given point.
$\\$The point is in Quadrant III.
Work Step by Step
RECALL:
$\\\\$For the point (x, y):
$\\\\$x=directed distance of the point from the y-axis (positive when to the right of the x-axis)
$\\$y=directed distance of the point from the x-axis (positive when above the y-axis)
$\\\\\\\\$This means that the given point is located $\frac{1}{2}$ unit to the left of the y-axis and 4 units below the x-axis.