Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 4 - Cumulative Review - Page 252: 20

Answer

$-2 \lt x \lt 1$ $\\\\$Graphing the inequality gives:

Work Step by Step

Multiply 3 to each part to have: $\\\\-1(3) \lt \dfrac{-2x-1}{3} \cdot 3 \lt 1(3) \\\\-3 \lt -2x-1 \lt 3$ $\\\\\\$Add $1$ to each part to have: $\\\\-3+1 \lt -2x-1+1 \lt 3+1 \\\\-2 \lt -2x \lt 4$ $\\\\\\$Divide -2 to each part (note that this will flip the inequality symbol) to have: $\\\\1 \gt x \gt -2 \\\\-2 \lt x \lt 1$
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