Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 3 - Test: 16

Answer

y=-$\frac{1}{3}x$+$\frac{5}{3}$

Work Step by Step

(-1, 2); perpendicular to 3x-y=4 m=-$\frac{1}{3}$; (-1, 2) y-2=-$\frac{1}{3}$(x-(-1)) 3(y-2)=-1(x+1) 3y-6=-x-1 3y=-x+5 $\frac{3y}{3}$=$\frac{-x}{3}$+$\frac{5}{3}$ f(x)=-$\frac{1}{3}$+$\frac{5}{3}$ y=-$\frac{1}{3}$+$\frac{5}{3}$
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