Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 3 - Section 3.7 - Graphing Linear Inequalities - Exercise Set - Page 187: 6

Answer

see graph

Work Step by Step

Changing the given inequality, $ 2x+y>2 ,$ to equality and then isolating $y$ result to \begin{array}{l}\require{cancel} 2x+y=2 \\\\ y=-2x+2 .\end{array} Use the table of values below to graph this line. Since the inequality used is "$ \gt $", use broken lines. Using the test point $( 0,0 )$, then \begin{array}{l}\require{cancel} 2(0)+0>2 \\\\ 0>2 \text{ (FALSE)} .\end{array} Since the solution above ended with a $\text{ FALSE }$ statement, then the test point is $\text{ NOT part }$ of the solution set.
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