Answer
see graph
Work Step by Step
Changing the given inequality, $
3x-2y\le12
,$ to equality and then isolating $y$ result to
\begin{array}{l}\require{cancel}
3x-2y=12
\\\\
-2y=-3x+12
\\\\
y=\dfrac{-3}{-2}x+\dfrac{12}{-2}
\\\\
y=\dfrac{3}{2}x-6
.\end{array}
Use the table of values below to graph this line.
Since the inequality used is "$
\le
$", use a solid line.
Using the test point $(
0,0
)$, then
\begin{array}{l}\require{cancel}
3(0)-2(0)\le12
\\\\
0-0\le12
\\\\
0\le12
\text{ (TRUE)}
.\end{array}
Since the solution above ended with a $\text{
TRUE
}$ statement, then the test point is $\text{
part
}$ of the solution set.