## Intermediate Algebra (6th Edition)

$y+\frac{5}{6}x=\frac{-38}{6}$
The slope is: $m=\frac{-3-(-8)}{-4-2}$ $m=\frac{5}{-6}$ Now substitute an ordered pair and the slope into point slope form: $y+8=\frac{-5}{6}(x-2)$ $y+\frac{5}{6}x=\frac{10}{6}-8$ $y+\frac{5}{6}x=\frac{-38}{6}$