Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 3 - Section 3.5 - Equations of Lines - Exercise Set: 23

Answer

$y=-2x+1$

Work Step by Step

We are given the points $(-2,5)$ and $(-6,13)$. We can use the slope formula to find the slope of a line going through these points. $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{13-5}{-6-(-2)}=\frac{8}{-4}=-2$ Next, we can use this slope and one of the given points to write the line in the point slope form $y-y_{1}=m(x-x_{1})$. $f(x)=y-5=-2(x+2)=-2x-4$ Add 5 to both sides. $y=-2x+1$
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