## Intermediate Algebra (6th Edition)

Published by Pearson

# Chapter 3 - Section 3.5 - Equations of Lines - Exercise Set: 20

#### Answer

$y=-\frac{1}{5}x-\frac{26}{5}$

#### Work Step by Step

The given line has a slope of $-\frac{1}{5}$ and goes through the point (4,-6). We can write this line in point-slope form $y-y_{1}=m(x-x_{1})$ with $m=-\frac{1}{5}$ and $(x_{1},y_{1})=(4,-6)$. $y+6=-\frac{1}{5}(x-4)=-\frac{1}{5}x+\frac{4}{5}$ Subtract 6 from both sides. $y=-\frac{1}{5}x+\frac{4}{5}-\frac{30}{5}=-\frac{1}{5}x-\frac{26}{5}$

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