## Intermediate Algebra (6th Edition)

$y=-\frac{9}{10}x-\frac{27}{10}$
The given line has a slope of $-\frac{9}{10}$ and goes through the point (-3,0). We can write this line in point-slope form $y-y_{1}=m(x-x_{1})$ with $m=-\frac{9}{10}$ and $(x_{1},y_{1})=(-3,0)$. $y=-\frac{9}{10}(x+3)=-\frac{9}{10}x-\frac{27}{10}$