Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 3 - Section 3.5 - Equations of Lines - Exercise Set: 19

Answer

$y=-\frac{9}{10}x-\frac{27}{10}$

Work Step by Step

The given line has a slope of $-\frac{9}{10}$ and goes through the point (-3,0). We can write this line in point-slope form $y-y_{1}=m(x-x_{1})$ with $m=-\frac{9}{10}$ and $(x_{1},y_{1})=(-3,0)$. $y=-\frac{9}{10}(x+3)=-\frac{9}{10}x-\frac{27}{10}$
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