Answer
$y=\frac{2}{3}x+10$
Work Step by Step
The given line has a slope of $\frac{2}{3}$ and goes through the point (-9,4).
We can write this line in point-slope form $y-y_{1}=m(x-x_{1})$ with $m=\frac{2}{3}$ and $(x_{1},y_{1})=(-9,4)$.
$y-4=\frac{2}{3}(x+9)=\frac{2}{3}x+6$
Add 4 to both sides.
$y=\frac{2}{3}x+10$