Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 3 - Section 3.5 - Equations of Lines - Exercise Set: 18

Answer

$y=\frac{2}{3}x+10$

Work Step by Step

The given line has a slope of $\frac{2}{3}$ and goes through the point (-9,4). We can write this line in point-slope form $y-y_{1}=m(x-x_{1})$ with $m=\frac{2}{3}$ and $(x_{1},y_{1})=(-9,4)$. $y-4=\frac{2}{3}(x+9)=\frac{2}{3}x+6$ Add 4 to both sides. $y=\frac{2}{3}x+10$
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